List customer and product without sales hackerrank sql server oracle. Ask Question Asked 3 years, 5 months ago.


List customer and product without sales hackerrank sql server oracle id INNER JOIN Customer CU ON CU. The result is ordered by The easiest way would be to specify. month and now that i think of it SQL Server 2005 has You signed in with another tab or window. 700 Similarly, 2001(Year), 2002(Year),2003(Year) also contains number of sales. In neither of the solutions do you guarantee to generate the results with the correct ordering. A common use of Oracle's ROWID is to provide a (somewhat) stable method of selecting rows and later returning to the row to process it (e. The result includes the names of the city and product, as well as the total amount spent on the product, rounded to 2 decimal places. I do not own or make these questions. Tested it on SQL Server - works fine. The tables I'm using are: Customers. This repository contains MySQL solutions of the HackerRank-SQL-Intermediate-Certificate problems which I encountered during the test. First SQL returns this list โ€“> All customers who do not Hello coders, in this post you will get all the solution of HackerRank SQL Solutions. Note: Print NULL when there are no more names corresponding to an Given a sales table with sales amount stored in local currencies and an exchange rate table containing currency conversion rate, to get total sales amount in USD for each sales date I need query Ironically Oracle owns MySql. sql sql-server oracle hackerrank oracle-database hackerrank Generate the contest leaderboard. name as TableName, t. sale_id, p. Welcome to CarrY4U Product GitHub Copilot. You signed out in another tab or window. id If you want all customer and product combinations, then I would suggest: select c. 1 SQL Query and Information about Sales Order Line Number ; Oracle Script to Copy Responsibilites of one user account to another user account Emails generated by Oracle ERP are delivered to customer/Supplier with from email address as โ€œno-reply@oracle. you have to specify a maximum length of the list (100 in the sample query below). year in (2008,2007) group by fill. The total column was done by a friend and works as expected. name as TableName, TYPE_NAME(t2. product_name (category="product") Tables: Customer. quantity), 0) as quantity from customer c cross join product p left join invoice i on c. If we want to find the total count of sales for each month (instead of the total sales amount), replace the This T-SQL query SELECT city, Len(city) FROM station ORDER BY Len(city) returns table sorted by city, not by Len(city) - is this proper behavior? Hackerrank SQL challenge. Question Find customers who have never made an order. Customer GROUP BY a. Write a query that prints a list of employee names (i. Sales. 400 4. Time components can cause the code to do things you don't expect. sql sql-server hackerrank sql-query sqlserver So, after reading some other materials and trying a few different things, I think I have a correct query. Name, S. Ask Question Asked 7 years, 10 months ago. tables t where t. CustomerID = C. OrderDetails. In other words, I want to select all customers from the customer table where there is no entry for their customer number in the invoice table. coalesce is supported in both Oracle and SQL Server and serves essentially the same function as nvl and isnull. A user can grant permissions to other users to see things in their schema but an Oracle schema is essentially a user's workspace. Customer C ON I. CREATE TABLE #orders(OrderId int identity(1,1), CustNum int, Orderdate date) -- using system columns to populate demo data (I'm lazy) INSERT INTO #orders(CustNum,Orderdate) SELECT system_type_id, DATEADD(month,column_id*-1,GETDATE()) FROM sys. Please note, each year contains number of sales that products has made. I need to use the Adventurewalks2017 database for thisagain. Discussions. schema_id)+'. PRICE FROM CUSTOMERS C INNER JOIN ORDERS O ON C. [PS]. sales, last_year. You are viewing a single comment's thread. tables t inner join sys. We use cookies to ensure you have the best browsing Try this one if you want to get the whole row, (supports most RDBMS)SELECT a. challenge_id" could Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI here's some code that should work in SQL Server, Oracle, or MySQL: SELECT current_timestamp - CAST(d1. 15%. Focus on standard sql and you know enough for most companies . I've not used SQLfiddle much so I wasn't able to setup a test schema for this (yet). 66%. product_name FROM product WHERE product. Customers using Oracle Recruiting source better quality candidates, improve time to hire, and reduce recruiting expenses. Name To further gain more knowledge about joins, kindly visit the link below: Visual Representation of SQL Joins; Result, i do this select distinct city from station where regexp_like(city,'^[^aeiou]. The above logic works with or without time components. Unzip the packages to a local directory on the SQL SQL query: SELECT Name_Seller, Month, Value FROM SALES WHERE Value = (SELECT MAX(Value) FROM SALES GROUP BY Name_Seller); List customers who sold most in mssql. The Oracle Cloud offers all the services you need to migrate, build, and run your IT, from existing enterprise workloads to new cloud-native applications and data platforms. system_type_id) as DataType, t2. * from sys. Return to all comments โ†’ Among several electronic database Management System, the 2 most well-liked and widely used are Oracle and SQL Server. But you need to add a terminating / after your code, on a line on its own - Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; T-SQL Challenges from hackerrank. Learn more about Foreign Keys. You can break this answer by switching the orders for customers 102 and 103. PRICE DESC I assume that you use SQL Server, this is why I use TOP 1. Google SQL Interview Question:https://youtu. ORDER_DATE <= DATEADD(year, 10, (SELECT MIN(ORDER_DATE) FROM ORDERS)) ORDER BY O. digit + d2. SQL query for overview of purchased products per user. invoice_id = i. rownum_rf, count(*) count_rfm, Users select their countries from a list I give to them, but the list is really huge so it would be great to have a SQL query that can avoid using that list, that is look in the DB and give back only those countries which are in the database, because for example I have nobody from Barbados, even if I have that option in the country select field Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test ๐ŸŽ“. Joining the subquery result to product table reduces the rows involved in that join. [ In this video I am solving the intermediate Certification Skills Test on Hackerrank. For example, if and , the calculation is . Explore my GitHub repository to learn from my experiences and find Let's say we have a Product table (product_id, product_name) and a Sales table (product_id, date, qty, amount). product_name; You're missing the ON keyword and there is the additional issue that in Oracle dates always have the components year, month, day, hour, minute and second and (assuming the NLS_DATE_FORMAT session parameter allows a valid cast from a string to a date) then '2017-12-31' will be converted to 2017-12-31T00:00:00 and your query will not select values that are SQL : List Customer And Product Without SaleTo Access My Live Chat Page, On Google, Search for "hows tech developer connect"I have a hidden feature that I pr Oracle supports the DATE keyword for introducing date constants using ISO-standard, unambiguous, non-locale-specific formats. Paneer 4. value), 0) total_value FROM Customers a LEFT JOIN Orders b ON a. Skills. CREATE TABLE products_sold ( product_id numeric(10) not null, 2 List Customer and Product Without Sale Using the UNION operator in one list return all customers who do not have an invoice and all products that were not sold For each customer without an invoice return - the string customer - the customer id - the customer name 2 For each product without an invoice return - the string product - the product id - the product name 4 The Install Oracle ODBC drivers on SQL Server. It will be updated everyday. I need a query that will list the total spent on both hair cuts and products for each customer in the customers table. SELECT count(*) /*count of transactions*/ FROM transactions WHERE /*Transactions in the last two months*/ transaction_date > DATEADD(mm, -2, GETDATE()) /*For customers that have had a sale today*/ customer_number in (SELECT customer_number List Customers and Products Without Sales Enter your query below. city_name ) SELECT SQL Server Oracle; CREATE TABLE products_sold ( product_id numeric(10) not null, customer_id INT not null, CONSTRAINT fk_pr FOREIGN KEY (customer_id) REFERENCES customer(id) ) GO. - Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions/Products Without Sales(solution-1,2). 06%. id (category="product") Name: customer. Input Format. Thomson Data offers just that. Sep 25, 2023 Marco Russo & Alberto Ferrari Power Pivot, and SQL Server Analysis Services. price = b. I am trying to generate results that show all customers that are in the customer table that have never placed an order and will therefore have no entry on the invoice table. It then orders them by the number descending and chooses the first row -- the customer with the most orders. CustomerID GROUP BY CustomerID HAVING COUNT(*) > 1) And another way for SQL Server 2005+: Below is the code in a SQL statement for SQL Server. product_id = p. * FROM tbProduct a INNER JOIN ( SELECT Category, MAX(Price) maxPrice FROM tbProduct GROUP BY Category ) b ON a. Medium SQL (Advanced) Max Score: 40 Success Rate: 93. Fund open source developers The ReadME Project. Surprisingly it does seem to understand PL/SQL; and even more surprisingly it handles the set serveroutput on, which is a SQL\Plus/SQL Developer client command. We then apply SUM() to calculate the total sales for each month, and group the results by year and month. sql hackerrank sqlserver hackerrank-solutions hackerrank Code Issues Pull requests Códigos em SQL (Oracle e MS Server), para aprendizado e referência. Customer_spending. it is wrong i Could you modify the first line of the select statement to: SELECT product, this_month. CustomerName, I. There are several basic variations between Oracle and SQL Server Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. SalesOrderDetail SOD on SOD. lstid , t. Easy SQL (Advanced) Max Score: 25 Success Rate: 97. The bitwise AND of all long integers in the inclusive range between and can be expressed as , where is the bitwise AND operator. a. id group by c. GitHub - MahedeiHasan/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions: Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test ๐ŸŽ“. Clarification: I want a row for each possible month/product tuple. Butter 3. You can toss a subquery in your WHERE clause to find customers that have had sales today:. Accelerate your Job Search. Given pairs of long integers, and , compute and print the bitwise AND of all natural numbers in the inclusive range between and . This arrangement allows multiple columns of IMAGE or Problem. Unsolved. customer_id and i. I used the table (values('x')) DUAL(DUMMY) to retrieve the result from a query that has a single column with an ANY result (in bold what writes the framework, in italic what I put as parameter): SELECT CASE WHEN 'X' = ANY (SELECT COLUMN FROM TABLE) THEN 1 Explanation: In this query, we use the YEAR() and MONTH() functions to extract the year and month from the Order_date column. Oracle also has a number of legacy data dictionary views-- TAB, DICT, TABS, and CAT for example-- that could be used. Hopefully it's not a big difference but I suspect at least the CASE statement isn't the same on Oracle. city_id = CI. [Y]. I had to write a particular query in a framework that write query by itself. Again, this is a rank-without-ties query. am, tg. sql files for the solutions I submitted! I do not think this answer is correct, although it does produce the correct result. Here's their snippet that won't seem to run for me in Chrome. SQLSyntaxErrorException: ORA-01795: maximum number of expressions in a list is 1000 for above expression. โ€“ How to Earn SQL (Advanced) Certification on Hackerank ? In this video, you'll learn how to earn free certification from Hackerrank*****Impor In standard SQL, you would write: SELECT customer_num, COUNT(*) FROM AllOrder GROUP BY customer_num ORDER BY COUNT(*) DESC FETCH FIRST 1 ROW ONLY; This aggregates the data by customer, counting the number of orders. id and ii. 2821 verified user reviews and ratings of features, pros, cons, pricing, support and more. The query should return all customers ,even customers without invoices and also products,even those products that were not sold. ProductID = P. Compare Oracle Database vs Microsoft SQL Server. 7. This is a new question Hackerrank has added for the advance level SQL certification. Name, COUNT(b. : the name attribute) from the Employee table in alphabetical order. NAME, O. ORACLE database : Y ORACLE table name : PS. Ask Question Asked 7 years, 10 Line 12 Invalid column name 'challenges_created'. You need to make sure that the Data Source is an alias that the tnsnames file knows about (on the server where SQL Server resides, regardless of where you're running the queries from); SQL Server is going to be just like any other Oracle client and needs to know where to connect to and without the tnsnames. city_name, pr. ProductID LEFT JOIN I believe the following query should work to identify the customer name with the highest amount derived from all orders in the current calendar year:. The database is SQL Server 2008 R2. Top Competitors. sku, product. SQL : Select the latest sale for each product. invoice_id and ii. digit as int) FROM ( SELECT digit FROM ( select '1' as digit union select '2' union select '3' union I had a simil issue. 99%. Question 1: Which products The following is a much better solution to the problem: WITH RankedOccupations AS ( SELECT NAME, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN OCCUPATION = 'Doctor' THEN NAME END) AS Doctor, MAX(CASE WHEN OCCUPATION = 'Professor' The company president would like the sales listed starting with the highest amount first. SELECT Distinct Name FROM Production. There are many factors that determine how the database resolves the query, object statistics, SYS schema statistics, and parameters, as well as server performance. 300 3. Considering your data model and requirements, you should try the below SQLs. In SQL Server SET NOCOUNT affects the behaviour even in non-interactive scenarios. Try this:-- custom table information select schema_name(t. id = cu. be/35gj How can I achieve the following in oracle without creating a stored procedure? Data Set: question_id element_id 1 7 1 8 2 9 3 10 3 You signed in with another tab or window. Problem. Customers achieve breakthrough performance, cost efficiencies, and security for business-critical workloads with Oracle servers. customer_name, p. No, in Oracle there is no SELECT without FROM. ) This article analyzes the performance of different DAX techniques to identify any products without sales in an area or a time period. sql files for the solutions I submitted! Hacker Rank SQL. product_id; Output: Consider two non-negative long integers, and , where . category AND a. Leaderboard. - mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions Customer Stories Partners Executive Insights Open Source GitHub Sponsors. ID WHERE O. id=orders. Submissions. Based on his total column, I've added the Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Can anyone help? There were a number of contests where participants each made number of attempts. _____ SUBSCRIBE!Do you want to understand how to solve SQL My journey of earning a SQL certification and tackling HackerRank SQL challenges. Below are seven examples of the kinds of problems a data scientist or software engineer might face during a technical interview. Calculating Sales Count. : enclosed in parentheses). Output the first name of the customer. Curd Now, 2000(Year) contains number of sales. Print NA for null customers or product or null quantity . Now, Now, the question is to find the product with highest number of sales. sales, last_month. Using the UNION operator, return a single list that includes all customers who do not have an invoice and all products that were not sold. The syntax for foreign keys is the same in Oracle and SQL Server. TransactionDate, I. It focuses solely on offering correct answers for SQL queries, joins, and aggregations, helping users pass the certification efficiently. the basic idea is to exploit oracle's hierarchical queries. Business_expansion. So, prior to summing up, you'll have to find the min and max of the dates, manipulate them such that they form "whole" weeks, and then run your original query with a WHERE that limits the date values according to the new range. *[^aeiou]$','i') and regexp_like(city,'^[^aeiou]\\w+[^aeiou]$','i'); . Please check 1. MS SQL Server's schemas are namespaces. object_id = t. List all sales along with the corresponding product names. New Companies. Use The UNION Operator In This Query. Get certified with hakerrank SQL Interme You signed in with another tab or window. The OCCUPATIONS table is described Contains solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test ๐ŸŽ“. Customer Relationship Management (CRM) Information Technology We use both Oracle and Microsoft SQL Server for our entire product line, using the best features of each of them to solve SELECT TOP 1 C. Step 1: Install Oracle ODBC drivers on server. SELECT first_name from customers WHERE first_name not in (select first_name from customers join orders on customers. CustomerID WHERE EXISTS(SELECT 1 FROM Invoice WHERE CustomerID = I. 0 Several of the answers above will work around the lack of a direct reference to a specific row, but will not work if changes occur to the other rows in a table. For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S). I tried below query and it worked for me. id = ii. Modified 2 years, Cannot reproduce this behavior in SQL Server 2016 - works as anyone would have guessed patients is the table name which has the first name and last name column. SELECT customer_name, COUNT(DISTINCT product_ID) as products_count FROM customer_table INNER JOIN orders_table ON customer_table. You signed in with another tab or window. category = b. all_columns -- In this video we will discuss an SQL interview question that was asked in meesho's HackerRank online test. That site doesn't seem to ever show your the output from your submission, unhelpfully, but does with just 'run code'. While you can have Accounting and Marketing schemas, they are not tightly-coupled to individual users. What I need is the total purchase amount. By detailing sales figures per city and identifying customers who spent 25% or less than This works for Oracle PL/SQL. Example 1 without empty rows: product ,year ,month from sales --this ideally would be from a products table cross join tm where year in (2008,2007)) fill where fill. Category ,fill. Status. SQL (Basic) SQL Product Actions. Create linked server on SQL server using System DSN. The problem is that customer 102 only has 1 order (both records are orderId 9), but this subselect will treat customer 102 as having 2 orders. quantity), 0) AS quantity FROM customer c LEFT JOIN invoice i on c. The below makes two passes of the data, but returns correct results in each case. Query the number of ocurrences of each Hackerrank Intermediate SQL certification solutions with basic SQL quarries, Sub quarries and Aggregation functions. product_name, ROUND(sum(ii. SELECT C. Note: Print NULL when there are no more names corresponding to an occupation. I'm trying to calculate the total purchase amount of each customer from the database available online on W3 Schools. name = 'MyTableName' -- table columns information select schema_name(t. Need to get MAX selling price in last 4 transaction. GitHub community articles Products Without Sales(solution I have an attendance table for the employees like the following ID Employee-ID Date Coming-time Leaving-time Break(in hours) 1 1 2016-01-01 08:00:00 18: This repository contains MYSQL solutions of HackerRank-SQL-Intermediate-Certificate problems which I encountered during the test . You can easily perform UNION with both the SQLs. city_name,COUNT(city_id) AS cnt , AVG(COUNT(city_id)) OVER() avg_cnt FROM COUNTRY CO INNER JOIN City CI ON CI. maxPrice Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. We use cookies to ensure you have the best browsing experience on our website. Medium SQL (Intermediate) Max Score: 30 Success Rate: 96. We use cookies to Link to SQL Code on GitHub: The goal of this project is to analyze data from a sales records database for scale model cars and extract information for decision-making. sql and 2. - adminazhar/-hackerrank-SQL-intermediate-skills-certification-test-solution Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. Getting java. line_total_price), 2) as tot from city ci, customer cu, invoice i, invoice_item ii, product pr where ci. Please append a semicolon "" at the end of the query. Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; SQL Server: Show a list of Customers that have more Orders than a specify Customer. Easy SQL (Intermediate) Max Score: 30 Success Rate: 94. ODCI*LIST types as they can hold 32767 items but it is a limitation on SQL functions that their expression list can have a maximum of 999 arguments. id = i. It showcases my growth, challenges faced, and solutions offered. Automate any workflow Solution for some HackerRank challenges by SQL Server. Binary Tree Nodes. customer_ID = orders_table. Data Two tables: Customers and Orders. Order by Sales Data for all customers and products. sales and see if those three sales numbers are correct. ID, a. product_name, coalesce(sum(ii. Medium SQL (Intermediate) Max How to Earn SQL (Advanced) Certification on Hackerank ? In this video, you'll learn how to earn free certification from Hackerrank*****Impor This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. Ask Question Asked 3 years, 5 months ago. create or replace function [schema]. Example here:. Seems to be a little bit simpler. 50%. Oracle is the only technology provider with a complete suite of integrated cloud applications and a cloud infrastructure platform. (SELECT *, 'Top 10' FROM sales ORDER BY sales_amount DESC LIMIT 5) UNION (SELECT *, 'Bottom 10' FROM sales ORDER BY sales_amount ASC LIMIT 5) ORDER BY sales_amount DESC; which gives the required result, without CTEs. To me learning pl/sql or t/sql is no different than learning any other programming language and youโ€™re always learning something new. select d. Oracle supports operating systems such as Windows, Linux, Solaris, HP-UX, OS X, etc. units_sold, this_month. id NOT IN (SELECT product_id FROM invoice_item); ----- Products Product GitHub Copilot. 1. Input Format The Employee table containing employee data for a company is described as follows: You can use two window functions to calculate difference between consequtive dates and sliding window with ROWS offset to count distinct preceiding consequtive days. [SQL] Using Oracle in HackerRank question, largest and smallest city name. Oracle SQL specifically. I was not able to solve it at all. The physical and logical storage methods for IMAGE and TEXT data differ from Oracle to Microsoft SQL Server. ora file, it's not going to know the List Customer And Product Without Sale In One List Return, All Customers Who Do Not Have An Invoice And All Products That Were Not Sold. From the MS docs "For stored procedures that contain several statements that do not return much actual data, this can provide a significant performance This query joins the Sales and Products tables on the product_id column, groups the results by product name, and calculates the total sales revenue for each product. Products. QNTY FROM CUSTOMER_T CUST, ( The question title is not very helpful. You can construct and populate a list in PL/SQL with more than 1000 items and pass it to the SQL statement and it will work db<>fiddle and you can pass more than 1000 select ci. country_id = CO. (There are some important differences, coalesce can take an arbitrary number of arguments, and returns the first non-null one. You switched accounts on another tab or window. Invoice I INNER JOIN dbo. Customer Spending. Msg 4104, Level 16, State 1, Server WIN-ILO9GLLB9J0, Line 9 The multi-part identifier "Challeneges. with gen as ( select 1 as cust_id, (date '2020-01-10') + 1 as q from dual union all select 1, (date '2020-01-10') + 2 as q from dual union all select 1, (date '2020-01-10') + 3 as q How can we rewrite this SQL query without IN clause [also without rownumber concept in use], as ORACLE is having restriction for IN clause. SELECT productid FROM product where purchase_date > sysdate-30; Remember this sysdate above has the time component, so it will be purchase orders newer than 03-06-2011 8:54 AM based on the time now. What sql query would return the monthly sales per product, and include products with no sales? (I'm using sql server if that makes any difference). Customers also increase uptime for Oracle applications by running them on any Oracle server and Java applications run 2X faster on Oracle SPARC servers using unique, built-in accelerators. Reload to refresh your session. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. If I understand correctly, you are looking for the top 50 sales for customers based on 2011 data - and want to see all years data for those top 50 from 2011, regardless of those customers being in the top 50 for other years. customer_id left join invoice_item ii on ii. Product P LEFT JOIN Sales. PSDBOWNER SQL SERVER Name: X I tried below query in my SSMS select * from [X]. The columns are: Customer name, Year, Month, and Revenue. That is my criteria for which answers fall technically short. Many thanks, Mike SQL (Intermediate) It includes complex joins, unions, and sub-queries. name from ( select substr( csv , instr(csv,',',1,lev) + 1 , instr(csv,',',1,lev+1 )-instr(csv,',',1,lev)-1 ) lstid from (select ','||'1,2,3,4,5'||',' csv from dual Watch all Easy Hackerrank SQL Problems solved in this video. Find and fix vulnerabilities Actions Customer Stories Partners Executive Insights Open Source GitHub Sponsors AmareshMuddebihal / HackerRank-SQL List Customer and Product Without Sale Using the UNION operator, in one list return all customers who do not have an invoice and all products that were not sold. I can list them all but not just the ones I want, might not understand Rank(), ROW_NUMBER(), FIRST_VALUE use in Oracle. 0. Generate the following two result sets: Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i. ORDER_ID = O. Return 3 Values: - Category - Is This Line Related To "Customer" Or "Product"? Print "Customer" Or "Product" Without Quotes. 3. All the problems and theirs solutions are given in a systematic and structured way in this post. Create System DSN to Oracle database on SQL Server. This collection provides solutions to the HackerRank SQL Certification Test problems. This makes it portable to MySQL for example. This is appears to be a query that can be solved with relational division and one way to achieve that is by utilizing nested NOT EXISTS queries. With HackerRank and Oracle Recruiting, customers can standardize their global technical recruiting The quickest path to approach companies that use Oracle lies in incorporating target-specific information into promotional efforts. here I want to combine the first and last names in the new column, which is the full name so I'm using CONCAT. Using the dual table is a good practice. SELECT Customer , Month , COUNT(ReceiptNo) AS Visits , SUM(Revenue) AS Revenue FROM (SELECT customer_first_name || ' ' || customer_middle_initial || '. sql & 2. List the top 1 customer's transactions who have the highest total transaction amount in such a way that the result shows all the transaction done by the customer and the last row shows the total amount of all the transaction done by the customer. Medium SQL (Intermediate) Max Solved queries for the Hackerrank SQL (Intermediate) Skills Certification Test ๐ŸŽ“. No need to get emotional about it. ' || I linked ORACLE Database in my local sql server called X. customer_name (category="customer") or product. Once upon a time, dual had two records (hence the name) and was intended to serve as a dummy recordset to duplicate records being joined with. 1. Oracle isn't the problem Created an ODBC connection to the database on the Oracle server on this machine; Restarted MS SQL Server; Created a linked server (Microsoft OLEDB Provider for ODBC Drivers) in the SQL instance; When connecting to the SQL Server using sqlcmd on this machine (I did not install SSMS there), I can query the linked database using OPENQUERY(). Print Prime Numbers. - DaveSV/HackerRank-SQL-Intermediate-Certificate The explanation section of the problem states: The results of the second query are ascendingly ordered first by number of names corresponding to each profession (2 <= 2 <= 3 <= 3), and then alphabetically by profession (doctor <= singer, and actor <= professor). Sqlserver vs. Some editing is likely required to make it run on Oracle. The EMPLOYEES table and the SALES_DEPT table contain the following columns: The customers should be listed alphabetically beginning with the letter 'A', and their corresponding order totals should be sorted from the highest amount to the lowest amount . g. Don't use BETWEEN on dates. select am, rf, rfm, count_rf, count_rfm, rownum_rf, rownum_rfm from ( -- next join the top 10 products to the data again to get -- the subproduct counts select tg. Business Expansion. country_name,CI. Sql skills are transferrable across most databases. The return type for isnull matches the type of the first argument, that is not true for coalesce, at least on SQL Server. Download the necessary Oracle Instant Client packages: Basic, ODBC, and SQL*Plus (optional) b. Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; I can do this on a calculator without any problems but writing the SQL is a different story. My solution: WITH MaxScores AS ( SELECT Hacker_ID, Challenge_ID, MAX(Score) AS MaxScore FROM Submissions GROUP BY Hacker_ID, Challenge_ID ), SummedScores AS ( SELECT Hacker_ID, SUM(MaxScore) AS TotalScore FROM MaxScores GROUP BY Hacker_ID ) SELECT S. At first I thought I'd just generate the tables in Oracle as SQL, manipulate the data formats, and run the query in SQL Server. nb: using dense_rank also allows for "top n per" result, e. Using the UNION operator, return a si the following solution for oracle is adopted from this source. Solve Challenge. List all the customer IDs and last names who have made more than 2 orders. For starters, the question was in the style: there is this feature in Oracle that is being missed in SQL Server and what is the recommended approach. SELECT c. Id (Category="Customer") Or That documentation suggests that the command only has effect when executing a statement at the SQL*plus prompt. ________ I have got the query working to pull customers monthly revenue from all the years for which the data is present. fn_table_numbers( numini integer, numfin integer, exponencial integer default 0 ) return tbl_numbers is numeros tbl_numbers; indice number; begin numeros := tbl_numbers(); for i in ( with tabla as (select numini, numfin from dual) select numini num from tabla union all select You'll have to omit those records in the addition which don't belong to a full week. e. List Customer and Product Without Sale Using the UNION operator, in one list return all customers who do not have an invoice and all products that were not sold. Finding the best selling item for each of your best customers in SQL. product_id = pr. Whereas SQL Server supports only windows and Linux operating systems. You'll notice some extra stuff in there to test if the sign of the row is negative. customer_ID, customer_name HAVING COUNT(DISTINCT product_ID) > 10 Verify your SQL Skills. txt at main · mahedei/Hackerrank-SQL-Intemediate-Skills-Certification-Test-Solutions SQL. customer_ID GROUP BY customer_table. Orders. I could set this query up in one Oracle database and make it run slow and make it run fast in another. '+t. InvoiceTotal FROM dbo. Milk 2. I have an Oracle 11g XE database that I would like to transfer into SQL Server Express 2005. But let say I only want to show the the city/cities where someone has done at least 2 orders, and that there are two customers living in this city/cities, so what I want to do is to pick out the city/cities where a customer has made at least 2 orders, but then show the Actions. Query: SELECT s. id group by The only one's this question deals with is the Customers table (stores customer details), the ProductSales table (store details about each product sale, and HairCuts table, store details about each cut. 2. By detailing sales figures per city and identifying customers who spent 25% or less than the average, this solution aids in strategic decision-making for optimizing sales and customer engagement. 200 2. This article talks about performing relational division in SQL in great detail and helped to clear things up a lot for me, Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; Oracle Setup: CREATE TABLE sales ( "DATE", Store, Sales ) AS SELECT DATE '2015-01-01', 'St01', 12123 FROM DUAL UNION ALL SELECT DATE '2015-01-01', 'St02', 3123 FROM DUAL UNION ALL SELECT @VasinYuriy That is not a limitation of the SYS. Automate any workflow Oracle schemas are like My Documents folders in the Windows OS. id (category="customer") or product. My current query gives me the product wise purchase amount for the customer. object_id Here is the first solution, which could be used as a working base. But I'm struggling to figure out how to get highest revenue month-year from this data. Medium SQL (Intermediate) Max Score: 30 Success Rate: 97. In Microsoft SQL Server, a pointer to the IMAGE or TEXT data is stored with the rows in the table while the IMAGE or TEXT data is stored separately. If you don't select DUMMY from it, it uses a special access path (FAST DUAL) which requires no I/O. - Id - Customer. com; Oracle ERP Cloud SQL Query to find Bank SELECT a. Find and fix vulnerabilities Contains solved queries for the Hackerrank SQL (Basic) Skills Certification Test ๐ŸŽ“. This repository contains all solutions and "thought process" to Hackerrank's SQL challenges. Concat is an SQl server function that takes a variable number of string arguments and concatenates (JOIN) them into a single string. product_name FROM Sales s JOIN Products p ON s. 2 IMAGE and TEXT Data Types (Binary Large Objects). In general, I would not suggest using these legacy views unless you absolutely need to backport your These concepts introduce more complex features and functionalities of SQL. TotalScore I have the following SQL statement that shows the total sales amount for customers in cities who have done at least 2 orders. Contribute to ejaj/SQL development by creating an account on GitHub. country_name, Ci. WITH CTE AS( SELECT DISTINCT CO. sql. Depending on the employerโ€™s technical interviewing tool, candidates can choose from a range of relational database tools, including DB2, MySQL, Oracle, and MS SQL Server. product_name, Coalesce((ii. Solved. customer_id LEFT JOIN invoice_item ii ON ---- Products Without Sales (solution_1) SELECT product. rf, ttc. dual is an in-memory table. All customers who do not have an invoice All products that were not sold Category: Is this related to "customer" or "product"? Print "customer or "product" ID: Customer. โ€“ Contribute to VivekSai07/Hackerrank-SQL-Intermediate-Skills-Certification-Test-Solution development by creating an account on GitHub. , This is a SQL query to get the total amount spent on each product in each city. comโ€ instead of no-reply@client-DomainName. This intermediate SQL solution provides insights into product sales across cities, offering a comprehensive overview of customer spending patterns. rfm, tg. city_id and cu. id GROUP BY CO. count_rf, tg. cust_id) Oracle Products, Solutions, and Services. The fact that Oracle has a feature that SQL Server does not seems to generate all kinds of reactions towards the disputable characteristics of this feature. columns t2 on t2. Please check 1. digit + d3. changing the where clause to where rnk <= 5 would list top 5 selling products per city. Customer) totalOrders, COALESCE(SUM(b. Write better code with AI Security. Marco and Alberto have worked with Analysis Services, Power BI and Power Pivot since the first Optimized for Oracle software. Watch also my other videos for more SQL Certification Solutions. Basic Join. Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. We segment the hosted information on Oracle customers comprehensively Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. SELECT CUSTOMER_NAME, Y. Hacker_ID, H. i created an oracle function that returns a table of numbers. They are essential for building more sophisticated and robust queries, managing data relationships, and optimizing query performance. ID = b. Download Sample Files. . 7 Advanced SQL Interview Questions. ipjow kiq roby dhedpc plpdbe haj pamlld sbdkwzxd yfut qkonv